Engineering Materials and Metallurgy MCQs 2026

78 questions with detailed answers · 27 from past papers · 8 quiz batches available

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Page 1 of 1Questions 1–10 of 78
  1. Q1easy

    Bronze traditionally is alloy of

    1. Acopper and tin
    2. Bcopper and zinc
    3. Ciron and nickel
    4. Dlead and tin only
    💡 Explanation:

    Bronzes used for bearings and statues.

  2. Q2hard

    Pearlite lamella spacing affects

    1. Aonly electrical resistivity of copper wire
    2. Bstrength and hardness with finer spacing giving higher strength
    3. Conly paint viscosity
    4. Donly air density at altitude
    💡 Explanation:

    Faster cooling through austenite produces finer pearlite.

  3. Q3medium

    Passivation of stainless steel uses

    1. Anitric or citric acid treatment to strengthen oxide film
    2. Bmolten zinc dip only
    3. Ccarburizing gas
    4. Dsand blasting only
    💡 Explanation:

    Removes free iron and enhances corrosion resistance.

  4. Q4easy

    Brass is an alloy of

    1. Acopper and zinc
    2. Bcopper and tin only
    3. Ciron and carbon
    4. Daluminium and magnesium only
    💡 Explanation:

    Zn in Cu improves machinability and strength.

  5. Q5easy

    Zinc coating on steel sheet is called

    1. Atinning only always
    2. Banodizing
    3. Cgalvanizing
    4. Dchromating only on aluminium
    💡 Explanation:

    Zn sacrificially protects steel.

  6. Q6hard

    Curie temperature of iron is about

    1. A770°C where ferromagnetism is lost
    2. B27°C
    3. C1538°C melting point
    4. D1147°C eutectic
    💡 Explanation:

    Above Curie point iron is paramagnetic.

  7. Q7easy

    Allotropy of iron means

    1. Airon never changes structure
    2. Biron exists in different crystal structures (BCC and FCC) at different temperatures
    3. Ciron is only liquid at room temperature
    4. Diron has no carbon solubility
    💡 Explanation:

    Alpha iron BCC; gamma austenite FCC.

  8. Q8hard

    Recrystallization temperature for metals is approximately

    1. A0.3 to 0.5 times absolute melting temperature
    2. Btwice melting point
    3. Croom temperature always for steel
    4. Dzero kelvin
    💡 Explanation:

    Rule of thumb for annealing after cold work.

  9. Q9hard

    Cold shortness is associated with

    1. Aonly high temperature forging
    2. Bexcess phosphorus making steel brittle at low temperature
    3. Conly austenite stability
    4. Donly copper plating
    💡 Explanation:

    Phosphorus raises ductile-brittle transition temperature.

  10. Q10hard

    Hot shortness in metals is cracking during hot work due to

    1. Alow-melting grain boundary films (e.g. copper in steel)
    2. Bonly cold temperature
    3. Conly high hardness
    4. Donly magnetic fields
    💡 Explanation:

    Sulphur and copper segregation can cause hot shortness.

  11. Q11medium

    Sintering temperature in PM is

    1. Aalways above liquidus
    2. Bat room temperature only
    3. Cbelow melting point of main constituent
    4. Dabove boiling point
    💡 Explanation:

    Diffusion bonds particles retaining porous structure optionally.

  12. Q12medium

    Powder metallurgy process sequence is typically

    1. Acasting, forging, welding only
    2. Bonly electroplating
    3. Conly extrusion of billet
    4. Dpowder production, compaction, sintering
    💡 Explanation:

    Sintering bonds particles below melting point.

  13. Q13Past Paper · PPSC/FPSC/NTShard

    Stress corrosion cracking needs

    1. Aonly compression in dry nitrogen
    2. Bonly cyclic impact in vacuum
    3. Conly annealing temperature
    4. Dtensile stress, susceptible alloy and corrosive medium together
    💡 Explanation:

    SCC can cause sudden failure at low apparent stress.

  14. Q14hard

    Intergranular corrosion follows

    1. Aonly crystal interiors uniformly
    2. Bgrain boundaries preferentially
    3. Conly external paint failure
    4. Donly magnetic domains
    💡 Explanation:

    Sensitization in stainless weld HAZ example.

  15. Q15medium

    Pitting corrosion is

    1. Auniform thickness loss only
    2. Bonly intergranular cracking always
    3. Clocalized attack forming small cavities
    4. Donly high-temperature oxidation
    💡 Explanation:

    Chlorides often initiate pits in stainless steels.

  16. Q16Past Paper · PPSC/FPSC/NTSmedium

    Galvanic corrosion requires

    1. Aonly one metal isolated in dry air
    2. Bonly plastic contact
    3. Celectrochemically dissimilar metals in common electrolyte with conductive path
    4. Donly identical metals touching in oil
    💡 Explanation:

    Noble and active metal couple drives corrosion.

  17. Q17medium

    Corrosion fatigue combines

    1. Aonly dry wear
    2. Bcyclic loading and corrosive environment
    3. Conly static tensile load in vacuum
    4. Donly thermal expansion
    💡 Explanation:

    Environment accelerates crack growth rate.

  18. Q18hard

    Endurance limit (fatigue limit) exists for

    1. Aall plastics always
    2. Ball ceramics at room temperature always
    3. Cmany ferrous alloys under reversed stress
    4. Dno materials ever
    💡 Explanation:

    Below this stress, fatigue life is very long.

  19. Q19Past Paper · PPSC/FPSC/NTSeasy

    Fatigue failure occurs under

    1. Aonly single overload above UTS
    2. Bonly at cryogenic temperatures always
    3. Ccyclic stresses below static yield strength
    4. Donly compressive static load
    💡 Explanation:

    Crack initiation and growth lead to sudden fracture.

  20. Q20Past Paper · PPSC/FPSC/NTSmedium

    Creep is

    1. Ainstant elastic stretch only
    2. Bfatigue at room temperature only
    3. Ctime-dependent plastic deformation under constant stress at high temperature
    4. Dhardness test indentation
    💡 Explanation:

    Important for turbines and boiler components.

  21. Q21medium

    Cupronickel alloys resist

    1. Aseawater corrosion
    2. Bonly organic acids in food only always
    3. Czero corrosion in all acids
    4. Donly high-temperature creep in gas turbines alone
    💡 Explanation:

    Used in marine heat exchangers and coins.

  22. Q22medium

    Hexagonal close-packed (HCP) structure is common in

    1. Acopper and aluminium primarily
    2. Bzinc, magnesium and titanium at room temperature
    3. Cpure iron at all temperatures
    4. Dlead only
    💡 Explanation:

    HCP metals include Zn, Mg, Ti (alpha).

  23. Q23Past Paper · PPSC/FPSC/NTSeasy

    Unit cell is

    1. Aa biological cell in plants
    2. Ba pressure vessel compartment only
    3. Cthe smallest repeating structural unit of a crystal lattice
    4. Da hydraulic cylinder chamber only
    💡 Explanation:

    Crystals are built by repeating unit cells in 3D.

  24. Q24Past Paper · PPSC/FPSC/NTSeasy

    Body-centered cubic (BCC) structure has atoms at

    1. Acorners and face centers only
    2. Bcorners and body center of the cube
    3. Cface centers only
    4. Dedge midpoints only
    💡 Explanation:

    BCC: 8 corners + 1 body diagonal center.

  25. Q25Past Paper · PPSC/FPSC/NTSeasy

    Face-centered cubic (FCC) structure has atoms at

    1. Abody center only with corners
    2. Bonly one corner
    3. Conly edge centers
    4. Dcorners and face centers
    💡 Explanation:

    FCC: close-packed with 4 atoms per cell effectively.

  26. Q26medium

    Coordination number in FCC is

    1. A8
    2. B6
    3. C4
    4. D12
    💡 Explanation:

    Each atom touches 12 nearest neighbours in FCC/HCP.

  27. Q27Past Paper · PPSC/FPSC/NTSeasy

    Grain boundaries in polycrystalline metals are

    1. Aregions of perfect single crystal
    2. Bonly surface oxide layers
    3. Cinterfaces between crystals with different orientations
    4. Dmolten metal pools
    💡 Explanation:

    Boundaries impede dislocation motion affecting strength.

  28. Q28Past Paper · PPSC/FPSC/NTSmedium

    Hall-Petch relation indicates yield strength increases as

    1. Agrain size decreases
    2. Bgrain size increases
    3. Ctemperature increases
    4. Dstrain rate decreases always
    💡 Explanation:

    Finer grains block dislocations; σy ∝ 1/√d.

  29. Q29medium

    Dislocation is

    1. Aa surface scratch only
    2. Ba line defect in crystal lattice responsible for plastic deformation
    3. Ca gas bubble in casting only
    4. Da type of grain boundary
    💡 Explanation:

    Edge and screw dislocations enable slip at lower stress.

  30. Q30medium

    Slip in crystals occurs on

    1. Arandom planes only
    2. Bclose-packed planes in close-packed directions
    3. Conly grain boundaries always
    4. Donly external surfaces
    💡 Explanation:

    Resolved shear stress on slip systems causes yield.

  31. Q31Past Paper · PPSC/FPSC/NTSeasy

    Young's modulus measures

    1. Astiffness in elastic region (stress/strain slope)
    2. Bplastic ductility only
    3. Chardness indentation only
    4. Dthermal expansion only
    💡 Explanation:

    E = σ/ε in Hooke's law region.

  32. Q32Past Paper · PPSC/FPSC/NTSeasy

    Yield strength is the stress at which

    1. Afracture occurs always
    2. Bmaterial begins significant plastic deformation
    3. Celastic limit is undefined always
    4. Dcreep starts at all temperatures
    💡 Explanation:

    0.2% offset method common for metals.

  33. Q33easy

    Ultimate tensile strength is

    1. Astress at fracture always on same scale
    2. Belastic limit only
    3. Chardness number in Brinell
    4. Dmaximum stress on engineering stress-strain curve
    💡 Explanation:

    UTS is peak load divided by original area.

  34. Q34easy

    Ductility is often expressed by

    1. Apercent elongation or reduction in area
    2. BYoung's modulus value
    3. Cmelting point in Kelvin
    4. Dthermal conductivity only
    💡 Explanation:

    Large elongation indicates ductile material.

  35. Q35Past Paper · PPSC/FPSC/NTSmedium

    Brittle fracture shows

    1. Alittle plastic deformation before failure
    2. Bnecking and cup-cone fracture always
    3. C50% elongation minimum
    4. Donly ductile dimple rupture
    💡 Explanation:

    Cleavage or rapid crack propagation typical.

  36. Q36Past Paper · PPSC/FPSC/NTSmedium

    Charpy impact test measures

    1. Aenergy absorbed by notched specimen at given temperature
    2. Bsurface roughness Ra
    3. Celectrical resistivity
    4. Dmagnetic permeability only
    💡 Explanation:

    Transition temperature indicates toughness loss.

  37. Q37Past Paper · PPSC/FPSC/NTSeasy

    Iron-carbon equilibrium diagram eutectoid point is at

    1. A4.3% C at 1147°C
    2. B0% C at 1538°C
    3. C0.76% C at 727°C
    4. D2.11% C at 727°C
    💡 Explanation:

    Eutectoid: austenite → pearlite.

  38. Q38Past Paper · PPSC/FPSC/NTSeasy

    Pearlite microstructure consists of

    1. Aonly austenite grains
    2. Balternating lamellae of ferrite and cementite
    3. Conly martensite plates
    4. Donly graphite flakes
    💡 Explanation:

    Eutectoid product in steel near 0.76% C.

  39. Q39easy

    Cementite chemical formula is

    1. AFe₃C
    2. BFeO
    3. CFe₂O₃
    4. DFe₃O₄
    💡 Explanation:

    Iron carbide intermetallic; hard and brittle.

  40. Q40Past Paper · PPSC/FPSC/NTSmedium

    Austenite is

    1. ABCC ferrite at room temperature
    2. Bonly liquid iron
    3. Conly cementite plates
    4. Dsolid solution of carbon in gamma iron (FCC)
    💡 Explanation:

    γ-iron stable at high temperature; non-magnetic.

  41. Q41Past Paper · PPSC/FPSC/NTSmedium

    Martensite is formed by

    1. Aslow furnace cooling only
    2. Bhot rolling only
    3. Crapid quenching of austenite
    4. Dannealing above 1000°C for days
    💡 Explanation:

    Diffusionless transformation gives hard brittle structure.

  42. Q42medium

    Hardenability measures

    1. Aonly surface hardness of aluminium
    2. Bdepth to which steel hardens upon quenching
    3. Conly copper conductivity
    4. Donly cast iron graphite size
    💡 Explanation:

    Jominy end-quench test ranks hardenability.

  43. Q43medium

    Normalizing involves heating above Ac₃ and cooling in

    1. Afurnace at 1°C/hour
    2. Boil quench
    3. Cliquid nitrogen
    4. Dstill air
    💡 Explanation:

    Faster than annealing; refines grains.

  44. Q44Past Paper · PPSC/FPSC/NTSmedium

    Tempering of martensite

    1. Aincreases carbon in martensite by diffusion always instantly
    2. Beliminates all iron
    3. Creduces brittleness and internal stress while lowering hardness somewhat
    4. Dconverts to liquid
    💡 Explanation:

    Tempering reheats quenched steel below A₁.

  45. Q45medium

    Carburizing adds carbon to surface using

    1. Aonly water quench
    2. Bonly sand blasting
    3. Ccarbon-rich atmosphere or pack at elevated temperature
    4. Donly anodizing
    💡 Explanation:

    Low-carbon steel surface becomes high-carbon after diffusion.

  46. Q46hard

    Nitriding forms hard surface by

    1. Aadding sulphur only
    2. Bremoving all carbon
    3. Celectroplating copper only
    4. Ddiffusing nitrogen into steel (often alloy steels)
    💡 Explanation:

    Produces wear-resistant case without quench distortion.

  47. Q47Past Paper · PPSC/FPSC/NTSeasy

    Grey cast iron microstructure contains

    1. Agraphite flakes in ferrite/pearlite matrix
    2. Bnodular graphite spheres primarily
    3. Cno graphite
    4. Donly martensite
    💡 Explanation:

    Flake graphite gives good machinability and damping.

  48. Q48Past Paper · PPSC/FPSC/NTSmedium

    Ductile (nodular) cast iron obtains graphite shape by

    1. Arapid oil quench only
    2. Badding magnesium or cerium inoculant
    3. Cremoving all carbon
    4. Dsand casting without cores only
    💡 Explanation:

    Spheroidal graphite improves tensile strength and ductility.

  49. Q49medium

    White cast iron has carbon as

    1. Agraphite flakes only
    2. Bgraphite nodules only
    3. Cno iron carbide
    4. Dcementite without free graphite
    💡 Explanation:

    Very hard and brittle; used as wear surface or malleablized.

  50. Q50Past Paper · PPSC/FPSC/NTSeasy

    Stainless steel resists corrosion primarily due to

    1. Achromium forming passive oxide film (typically ≥11% Cr)
    2. Bhigh carbon only
    3. Clead content
    4. Dzinc coating only
    💡 Explanation:

    Chromium oxide layer protects base metal.

  51. Q51medium

    Segregation in castings causes

    1. Aperfect homogeneity always
    2. Bonly surface polish
    3. Conly magnetic alignment
    4. Dnon-uniform composition and properties
    💡 Explanation:

    Last-to-freeze regions rich or lean in solutes.

  52. Q52Past Paper · PPSC/FPSC/NTSmedium

    Aluminium alloys are often strengthened by

    1. Aonly carburizing
    2. Bonly nitriding
    3. Cprecipitation hardening (age hardening)
    4. Donly white iron formation
    💡 Explanation:

    Duralumin: solution treat and age to form precipitates.

  53. Q53medium

    Martensitic stainless steels are

    1. Ahardenable by heat treatment; magnetic
    2. Balways non-magnetic FCC
    3. Ccannot be quenched
    4. Dcontain no chromium
    💡 Explanation:

    410, 420 used for cutlery and blades.

  54. Q54medium

    Inoculation in cast iron promotes

    1. Aonly cementite formation always
    2. Bonly gas porosity
    3. Conly martensite in cast iron
    4. Dgraphite nucleation for desired graphite form
    💡 Explanation:

    FeSi inoculant controls solidification structure.

  55. Q55easy

    Thermosetting plastics once cured

    1. Asoften reversibly like wax always
    2. Bbecome metals
    3. Ccannot be re-melted without degradation
    4. Devaporate instantly
    💡 Explanation:

    Epoxy, phenolic form cross-linked network.

  56. Q56easy

    Thermoplastics can be

    1. Aonly cured irreversibly like thermosets always
    2. Bre-melted and reshaped repeatedly
    3. Conly used as liquids always
    4. Dnever injection moulded
    💡 Explanation:

    PE, PP, ABS reprocess on heating.

  57. Q57hard

    Glass transition temperature Tg of polymer is

    1. Amelting of iron carbide
    2. Bboiling of water
    3. Ctemperature where amorphous polymer becomes rubbery on heating
    4. DCurie point of nickel only
    💡 Explanation:

    Below Tg: glassy; above: rubbery (amorphous thermoplastics).

  58. Q58medium

    Fiber direction in composites primarily controls

    1. Aisotropic behaviour in all directions always
    2. Bonly colour
    3. Canisotropic strength and stiffness
    4. Donly density reduction only
    💡 Explanation:

    Loads along fibres carry highest stress.

  59. Q59easy

    Composite materials combine

    1. Aonly single pure element always
    2. Bmatrix and reinforcement for tailored properties
    3. Conly water and oil
    4. Donly one grain boundary
    💡 Explanation:

    Fibre-reinforced polymers and MMCs examples.

  60. Q60medium

    Titanium alloys advantage is

    1. Ahigh strength-to-weight ratio and corrosion resistance
    2. Blowest melting point of all metals
    3. Calways cheaper than mild steel
    4. Dcannot be welded ever
    💡 Explanation:

    Ti used in aerospace and chemical plant.

  61. Q61medium

    Superalloys are used in

    1. Aonly window glass
    2. Bonly concrete reinforcement bars at room service only
    3. Conly paper production only
    4. Dgas turbine hot sections for creep and oxidation resistance
    💡 Explanation:

    Ni-base superalloys withstand high temperature.

  62. Q62hard

    Bainite microstructure forms at

    1. Aonly instant quench to martensite always
    2. Bonly equilibrium slow cooling
    3. Conly gas phase
    4. Dintermediate temperature below pearlite nose on TTT
    💡 Explanation:

    Bainite: ferrite + carbide; tougher than martensite.

  63. Q63hard

    CCT diagram is more useful than TTT for

    1. Aonly isothermal holding forever
    2. Bonly tensile testing speed
    3. Conly hardness of rubber
    4. Dcontinuous cooling processes like actual quenching
    💡 Explanation:

    Continuous Cooling Transformation matches real quench curves.

  64. Q64Past Paper · PPSC/FPSC/NTSmedium

    Austenitic stainless steels (300 series) are

    1. Aalways martensitic BCC
    2. Bpure iron only
    3. Cnon-magnetic FCC with nickel and chromium
    4. Dalways cast iron
    💡 Explanation:

    304, 316 common; good corrosion resistance.

  65. Q65medium

    Eddy current testing is best for

    1. Aonly concrete structures
    2. Bonly wood timber
    3. Conly glass only
    4. Ddetecting surface and near-surface flaws in conductive materials
    💡 Explanation:

    Electromagnetic induction senses conductivity changes.

  66. Q66easy

    Dye penetrant inspection finds

    1. Asurface-breaking defects
    2. Bonly internal voids deep inside always without surface opening
    3. Conly magnetic domains
    4. Donly thermal conductivity
    💡 Explanation:

    Capillary action draws dye into cracks.

  67. Q67medium

    Magnetic particle inspection requires

    1. Aonly aluminium alloys always
    2. Bferromagnetic material
    3. Conly plastics
    4. Donly ceramics always
    💡 Explanation:

    Flux leakage at defects attracts particles.

  68. Q68medium

    Radiographic testing (RT) uses

    1. AX-rays or gamma rays to image internal defects
    2. Bonly visible light photography of surface
    3. Conly hammer ringing always
    4. Donly acid etching macro only
    💡 Explanation:

    RT reveals porosity, cracks, inclusions.

  69. Q69Past Paper · PPSC/FPSC/NTSeasy

    NDT method ultrasonic testing detects

    1. Aonly surface colour
    2. Bonly chemical composition quantitatively always
    3. Cinternal flaws using sound wave reflection
    4. Donly magnetic personality
    💡 Explanation:

    UT common for welds and forgings.

  70. Q70medium

    Vickers hardness uses

    1. Asteel ball 10 mm only
    2. Bsingle scratch line only
    3. Cpendulum rebound only
    4. Dsquare-based diamond pyramid indenter
    💡 Explanation:

    HV applicable to thin sections and all hardness ranges.

  71. Q71easy

    Rockwell hardness differs from Brinell by

    1. Ameasuring only scratch width optically always
    2. Busing only Charpy hammer
    3. Cmeasuring only electrical resistance
    4. Dmeasuring depth of penetration under load
    💡 Explanation:

    Rockwell gives quick direct dial reading.

  72. Q72Past Paper · PPSC/FPSC/NTSeasy

    Brinell hardness test uses

    1. Adiamond pyramid only always
    2. Bspring hammer rebound only
    3. Cultrasonic pulse only
    4. Dhardened steel or carbide ball indenter
    💡 Explanation:

    Large impression averages coarse structures like castings.

  73. Q73medium

    Recrystallization annealing after cold work

    1. Aincreases dislocation density further
    2. Bforms new strain-free grains
    3. Cconverts metal to gas
    4. Donly hardens surface by quench
    💡 Explanation:

    Heating above recrystallization temperature restores ductility.

  74. Q74Past Paper · PPSC/FPSC/NTSeasy

    Work hardening (strain hardening) increases strength by

    1. Adislocation density increase during plastic deformation
    2. Bgrain growth in annealing
    3. Cremoving all dislocations
    4. Donly heating above melting point
    💡 Explanation:

    Cold working raises strength, reduces ductility.

  75. Q75medium

    Solid solution strengthening adds

    1. Aonly surface paint
    2. Bonly lubricant oil
    3. Conly vacuum
    4. Dsolute atoms distorting lattice and impeding dislocations
    💡 Explanation:

    Alloying elements raise yield strength.

  76. Q76medium

    Lever rule on phase diagram calculates

    1. Ahardness from cooling rate
    2. Bmass fractions of two phases in two-phase region
    3. Celectrical conductivity only
    4. Dsurface tension only
    💡 Explanation:

    Tie-line proportions give phase amounts.

  77. Q77hard

    Phase diagram horizontal line indicates

    1. Avariable composition single phase only
    2. Bimpossible equilibrium
    3. Conly mechanical mixing
    4. Dinvariant reaction (eutectic, eutectoid or peritectic)
    💡 Explanation:

    Three phases coexist at invariant points.

  78. Q78Past Paper · PPSC/FPSC/NTSeasy

    Annealing heat treatment purpose is to

    1. Amaximize hardness always
    2. Bsoften metal, relieve stress and refine grain structure
    3. Cform martensite always
    4. Dincrease internal stress
    💡 Explanation:

    Heating and slow cooling homogenize structure.