Fluid Mechanics and Hydraulic Machines MCQs 2026

80 questions with detailed answers · 28 from past papers · 8 quiz batches available

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Page 1 of 1Questions 1–10 of 80
  1. Q1medium

    Non-Newtonian fluid example is

    1. Ablood or polymer solution
    2. Bwater at 20 °C
    3. Cair at low speed
    4. Dmercury
    💡 Explanation:

    Non-Newtonian fluids have variable apparent viscosity with shear rate.

  2. Q2easy

    Newton law of viscosity states shear stress is proportional to

    1. Arate of strain (velocity gradient)
    2. Bpressure only
    3. Cabsolute temperature only
    4. Ddensity squared
    💡 Explanation:

    τ = μ du/dy for Newtonian fluids.

  3. Q3Past Paper · PPSC/FPSC/NTSmedium

    Capillary rise in small tube is due to

    1. Asurface tension and wetting
    2. Bonly gravity increase
    3. Cturbulent mixing
    4. Dcompressibility
    💡 Explanation:

    Jurin height h = 2σ cos θ / (ρgr).

  4. Q4medium

    Metacentric height GM positive indicates

    1. Aalways capsizing
    2. Bneutral stability only
    3. Cstable floating equilibrium
    4. Dno restoring moment
    💡 Explanation:

    Positive GM gives restoring couple when vessel heels.

  5. Q5easy

    Buoyant force on submerged body equals

    1. Aweight of displaced fluid
    2. Bweight of body always
    3. Chalf displaced volume only
    4. Dsurface tension force
    💡 Explanation:

    Archimedes principle: Fb = ρgVdisplaced.

  6. Q6Past Paper · PPSC/FPSC/NTSeasy

    Hydrostatic pressure at depth h in liquid is

    1. Aρg/h
    2. Bh/ρg
    3. Cρgh
    4. Dzero at all depths
    💡 Explanation:

    Pressure increases linearly with depth in incompressible static fluid.

  7. Q7easy

    Pascal law in fluid statics states

    1. Apressure at a point is transmitted equally in all directions
    2. Bpressure increases with velocity always
    3. Cfluid always flows uphill
    4. Ddensity is constant in gases only
    💡 Explanation:

    Foundation of hydraulic jacks and force multiplication in enclosed fluids.

  8. Q8Past Paper · PPSC/FPSC/NTSmedium

    Energy grade line (EGL) includes

    1. Aonly static pressure
    2. Bonly elevation
    3. Cfriction factor value
    4. Dvelocity head in addition to piezometric head
    💡 Explanation:

    EGL = HGL + V²/2g represents total mechanical energy per unit weight.

  9. Q9medium

    Hydraulic grade line (HGL) represents

    1. Avelocity head only
    2. Bpiezometric head at each point along pipe
    3. Ctemperature profile
    4. DRe along pipe
    💡 Explanation:

    HGL = z + p/(ρg); lies below EGL by velocity head V²/2g.

  10. Q10medium

    Draft tube in reaction turbines serves to

    1. Arecover kinetic energy at outlet and maintain suction head
    2. Bincrease frictional loss only
    3. Cheat the water
    4. Dmeasure flow rate only
    💡 Explanation:

    Diffuser converts outlet velocity head to pressure below atmospheric at runner exit.

  11. Q11Past Paper · PPSC/FPSC/NTSmedium

    Kaplan turbine is suitable for

    1. Avery high head small flow
    2. Bzero water availability
    3. Ccompressed air only
    4. Dlow head and large discharge
    💡 Explanation:

    Adjustable-blade propeller-type turbine for low head hydro sites.

  12. Q12medium

    Francis turbine is classified as

    1. Apure impulse only
    2. Bwind turbine
    3. Cmixed-flow reaction turbine
    4. Dreciprocating engine
    💡 Explanation:

    Francis runner has radial inlet and axial outlet; pressure drop occurs in runner passages.

  13. Q13easy

    Gear pump belongs to category of

    1. Adynamic radial flow pumps
    2. Bpositive displacement pumps
    3. Cgravity pumps only
    4. Dturbines
    💡 Explanation:

    Intermeshing gears trap and transfer fixed volume of fluid each revolution.

  14. Q14Past Paper · PPSC/FPSC/NTSmedium

    Reciprocating pump delivers

    1. Aonly low pressure large flow always
    2. Bno pulsating flow ever
    3. Cnearly constant volume per stroke at high pressure
    4. Donly gases
    💡 Explanation:

    Positive displacement gives high pressure capability with pulsating discharge.

  15. Q15medium

    Multistage centrifugal pumps are used when

    1. Aonly very low head large flow
    2. Bhandling pure solids only
    3. Cvacuum generation only
    4. Dhigh head is required at moderate flow
    💡 Explanation:

    Stages in series add heads for boiler feed and high-rise water supply.

  16. Q16hard

    Specific speed of a centrifugal pump indicates

    1. Aonly electrical power factor
    2. Btype and shape suitable for given Q and H
    3. Coil viscosity grade
    4. Dsteam pressure only
    💡 Explanation:

    Ns classifies pump as radial, mixed or axial flow based on N, Q, H.

  17. Q17Past Paper · PPSC/FPSC/NTSmedium

    Cavitation in pumps is indicated by

    1. Asilent smooth operation
    2. Bnoise, vibration and pitting of impeller
    3. Cincreased NPSHa always
    4. Ddecreased temperature only
    💡 Explanation:

    Vapor bubble collapse damages metal and reduces performance.

  18. Q18medium

    NPSH available must exceed NPSH required to avoid

    1. Alaminar flow only
    2. Bincreased viscosity
    3. Ccavitation in pumps
    4. Dpositive gauge pressure always
    💡 Explanation:

    Insufficient suction head causes vapor bubbles forming and collapsing in the impeller.

  19. Q19easy

    Minor losses in pipe systems are caused by

    1. Aonly straight pipe friction
    2. Bgravity alone
    3. Cfluid density only
    4. Dfittings, bends, valves and sudden expansions
    💡 Explanation:

    K-factor losses h = KV²/2g at fittings add to friction losses.

  20. Q20Past Paper · PPSC/FPSC/NTSmedium

    Moody diagram relates friction factor to

    1. AReynolds number and relative roughness
    2. Bonly pipe length
    3. Conly fluid color
    4. Dcompressibility only
    💡 Explanation:

    Moody chart plots f vs Re for various ε/D values.

  21. Q21hard

    Friction factor for smooth pipes in turbulent region can be estimated by

    1. AArchimedes principle only
    2. BBlasius or Colebrook equation
    3. CPascal law only
    4. DCarnot efficiency formula
    💡 Explanation:

    Blasius f = 0.316/Re^0.25 for smooth turbulent pipe flow in moderate Re range.

  22. Q22medium

    Darcy-Weisbach equation gives

    1. Apump power directly
    2. BReynolds number value
    3. Chead loss due to friction in pipes
    4. Dsurface tension force
    💡 Explanation:

    hf = f(L/D)(V²/2g) where f is friction factor.

  23. Q23Past Paper · PPSC/FPSC/NTSeasy

    Turbulent flow in pipes is characterized by

    1. Airregular fluctuations and mixing
    2. Bsmooth layered streamlines only
    3. CRe below 100 always
    4. Dzero wall shear
    💡 Explanation:

    Turbulence has random velocity fluctuations enhancing mixing and wall shear.

  24. Q24medium

    For laminar flow in a circular pipe, velocity profile is

    1. Aparabolic with maximum at center
    2. Bflat plug flow always
    3. Clinear from wall to center
    4. Dzero everywhere
    💡 Explanation:

    Hagen-Poiseuille flow gives u = umax(1 − r²/R²) parabolic profile.

  25. Q25easy

    Kinematic viscosity is defined as

    1. Adynamic viscosity divided by density
    2. Bdensity times dynamic viscosity
    3. Cpressure divided by velocity
    4. DRe times diameter
    💡 Explanation:

    ν = μ/ρ; unit m²/s (Stokes in CGS).

  26. Q26Past Paper · PPSC/FPSC/NTSeasy

    Bernoulli equation for steady incompressible flow along a streamline states that

    1. Avelocity head alone is constant
    2. Bpressure always increases with height
    3. Ctotal head remains constant
    4. Dflow rate changes with pipe diameter only
    💡 Explanation:

    Bernoulli: p/ρ + V²/2 + gz = constant for ideal steady flow without shaft work or losses.

  27. Q27easy

    Continuity equation for incompressible flow in a pipe is expressed as

    1. Ap1 = p2 always
    2. BA1V1 = A2V2
    3. CQ changes with viscosity
    4. DRe is constant everywhere
    💡 Explanation:

    Mass conservation gives discharge Q = AV constant for incompressible flow.

  28. Q28easy

    Reynolds number Re is defined as

    1. AμVD/ρ
    2. BVD/g
    3. Cp/ρV²
    4. DρVD/μ
    💡 Explanation:

    Re = inertial forces / viscous forces; Re = ρVD/μ for internal pipe flow.

  29. Q29Past Paper · PPSC/FPSC/NTSeasy

    Dynamic viscosity unit in SI is

    1. Am²/s only
    2. BPa·s (N·s/m²)
    3. CN/m only
    4. Dkg/m only
    💡 Explanation:

    Dynamic viscosity μ has SI unit Pa·s; kinematic viscosity ν = μ/ρ in m²/s.

  30. Q30easy

    Flow in a smooth pipe is generally laminar when Reynolds number is below

    1. A4000
    2. B10000
    3. C500
    4. D2300
    💡 Explanation:

    Critical Re for pipe flow is about 2300; above 4000 flow is usually fully turbulent.

  31. Q31medium

    Boundary layer thickness increases along a flat plate because

    1. Apressure always decreases
    2. Bdensity becomes zero
    3. Cviscous effects diffuse momentum outward
    4. DRe decreases to zero
    💡 Explanation:

    Growing boundary layer results from momentum transfer from free stream toward the wall.

  32. Q32Past Paper · PPSC/FPSC/NTSeasy

    Centrifugal pump imparts energy to fluid mainly by

    1. Aincreasing kinetic energy then converting to pressure
    2. Bheating the fluid only
    3. Cdecreasing angular momentum
    4. Dcompressing vapor
    💡 Explanation:

    Impeller raises velocity; volute/diffuser converts velocity head to pressure head.

  33. Q33medium

    Pelton wheel is an example of

    1. Areaction turbine only
    2. Bimpulse turbine
    3. Cpositive displacement pump
    4. Dreciprocating pump
    💡 Explanation:

    Pelton uses high-velocity jets striking buckets; pressure drop occurs mainly in the nozzle.

  34. Q34hard

    Hydraulic ram utilizes

    1. Asteam expansion only
    2. Bwater hammer effect to pump a portion of water to higher elevation
    3. Celectromagnetic induction
    4. Dcentrifugal impeller only
    💡 Explanation:

    Ram uses kinetic energy of flowing water and valve closure shock to lift water.

  35. Q35Past Paper · PPSC/FPSC/NTSeasy

    Simple U-tube manometer measures

    1. Apressure difference as liquid column height difference
    2. Bmass flow rate directly
    3. CReynolds number
    4. Dturbine power only
    💡 Explanation:

    Δp = ρgh for manometer fluid column height h.

  36. Q36easy

    Venturi meter measures flow rate based on

    1. Atemperature rise in throat
    2. Bpressure difference between converging and throat sections
    3. Ccolor change of fluid
    4. Dmagnetic field strength
    💡 Explanation:

    Bernoulli effect: throat velocity increases and pressure drops; Δp relates to Q.

  37. Q37Past Paper · PPSC/FPSC/NTSmedium

    Orifice meter causes greater permanent pressure loss than venturi because

    1. Ait has a longer converging cone
    2. Bit measures temperature instead
    3. Cdischarge coefficient is unity
    4. Dno gradual recovery section after restriction
    💡 Explanation:

    Sudden contraction and lack of diffuser cause irrecoverable head loss in orifice.

  38. Q38Past Paper · PPSC/FPSC/NTShard

    Stokes law gives drag on small sphere as

    1. AFD independent of viscosity
    2. BFD proportional to V² only
    3. CFD = 3πμDV
    4. DFD zero in viscous flow
    💡 Explanation:

    Valid for Re < 1; used in viscometry and sedimentation.

  39. Q39medium

    Terminal velocity of falling particle occurs when

    1. Aacceleration is maximum
    2. BRe is infinite always
    3. Cdrag force equals net weight minus buoyancy
    4. Dviscosity is zero
    💡 Explanation:

    Equilibrium of forces gives constant maximum settling speed.

  40. Q40medium

    Pitot tube measures

    1. Astatic pressure only in all cases
    2. Bmass of fluid
    3. Cstagnation pressure to find local velocity
    4. Dturbine efficiency
    💡 Explanation:

    From stagnation and static pressure, V = √(2Δp/ρ).

  41. Q41Past Paper · PPSC/FPSC/NTSmedium

    Coefficient of discharge for venturi is typically

    1. Azero always
    2. Bhigher than for sharp-edged orifice
    3. Clower than orifice always
    4. Dexactly 1.0 always
    💡 Explanation:

    Gradual area change gives lower separation and Cd closer to unity.

  42. Q42easy

    Rotameter measures flow using

    1. Aelectromagnetic induction only
    2. Borifice plate only
    3. Cfloat equilibrium in tapered tube
    4. Dthermocouple
    💡 Explanation:

    Variable area meter: float rises until annular area balances drag and weight.

  43. Q43hard

    Weir flow measurement for rectangular sharp-crested weir varies discharge approximately as

    1. AH linearly only
    2. BH² only
    3. CH^(3/2)
    4. Dindependent of head
    💡 Explanation:

    Francis formula Q = (2/3)Cdb√(2g)H^(3/2) for rectangular weir.

  44. Q44Past Paper · PPSC/FPSC/NTSmedium

    Chezy and Manning formulas estimate

    1. Aclosed pipe laminar flow only
    2. Bvelocity or discharge in open channels
    3. Ccompressor performance
    4. DRankine cycle efficiency
    💡 Explanation:

    Open channel uniform flow based on hydraulic radius and slope.

  45. Q45easy

    Hydraulic radius R is defined as

    1. Aperimeter divided by area
    2. Bdiameter squared
    3. Cvelocity times area
    4. Dflow area divided by wetted perimeter
    💡 Explanation:

    R = A/P used in open channel and pipe flow calculations.

  46. Q46medium

    Froude number characterizes

    1. Aviscous to inertial forces only
    2. BMach number in liquids
    3. Cpump NPSH
    4. Drelative importance of inertia to gravity in open channel flow
    💡 Explanation:

    Fr = V/√(gL); Fr = 1 is critical flow.

  47. Q47Past Paper · PPSC/FPSC/NTShard

    Critical depth in rectangular channel occurs when

    1. ARe equals 2300
    2. Bflow is always subcritical
    3. CFroude number equals unity
    4. Ddepth is maximum always
    💡 Explanation:

    At critical depth specific energy is minimum for given discharge.

  48. Q48medium

    Hydraulic jump occurs in

    1. Alaminar to turbulent in pipe only
    2. Bpump suction line only
    3. Cclosed valve only
    4. Dsupercritical to subcritical transition
    💡 Explanation:

    Rapid increase in depth dissipates energy with turbulence.

  49. Q49easy

    Surface tension σ has unit

    1. APa·s
    2. BN/m
    3. Cm²/s
    4. Dkg/m³
    💡 Explanation:

    Surface tension is force per unit length acting at liquid interface.

  50. Q50Past Paper · PPSC/FPSC/NTSmedium

    Vapor pressure of liquid is important in pumps because

    1. Ait increases pipe roughness
    2. Bit eliminates friction loss
    3. Cit raises NPSHa always
    4. Dlow pressure can cause boiling and cavitation
    💡 Explanation:

    When local pressure drops below vapor pressure, cavitation begins.

  51. Q51hard

    Head developed by centrifugal pump for given impeller speed and diameter is independent of

    1. Afluid density
    2. Bimpeller diameter
    3. Crotational speed
    4. Dimpeller design
    💡 Explanation:

    Same pump develops same head in meters; pressure rise Δp = ρgH depends on density.

  52. Q52Past Paper · PPSC/FPSC/NTSmedium

    Affinity laws for pumps state flow rate varies with speed as

    1. AQ proportional to N²
    2. BQ proportional to N
    3. CQ independent of N
    4. DQ proportional to 1/N
    💡 Explanation:

    Pump laws: Q ∝ N, H ∝ N², Power ∝ N³ for same pump.

  53. Q53medium

    System curve for pipe network intersects pump curve at

    1. Ashutoff head only
    2. Bmaximum efficiency always
    3. Czero flow always
    4. Doperating point
    💡 Explanation:

    Intersection gives operating Q and H where pump and system losses balance.

  54. Q54hard

    Water hammer pressure surge depends on

    1. Aonly pipe color
    2. Bonly ambient temperature
    3. CRe only
    4. Dwave speed and velocity change
    💡 Explanation:

    Δp = ρaΔV for rapid valve closure; a is acoustic wave speed in liquid.

  55. Q55Past Paper · PPSC/FPSC/NTSmedium

    Surge tank in hydro penstock reduces

    1. Aturbine efficiency to zero
    2. Breservoir volume
    3. Cnet head permanently
    4. Dwater hammer pressure fluctuations
    💡 Explanation:

    Tank absorbs transient flow variations protecting conduit from excessive pressure.

  56. Q56medium

    Impulse turbine runner operates in

    1. Ahigh vacuum only inside blades always
    2. Bpressurized sealed casing only
    3. Catmospheric pressure region
    4. Doil bath
    💡 Explanation:

    Jet expands to atmospheric; buckets deflect water on impulse principle.

  57. Q57hard

    Degree of reaction for turbine is ratio of

    1. Aenthalpy drop in rotor to total enthalpy drop
    2. Bpower to speed
    3. Cinlet to outlet pressure only
    4. Dtorque to angular velocity only
    💡 Explanation:

    R = (h1−h2)/(h1−h3) indicates fraction of energy converted in runner.

  58. Q58Past Paper · PPSC/FPSC/NTShard

    Cavitation parameter σ for turbines relates to

    1. Aonly steam quality
    2. BNPSH and net head
    3. Cfuel air ratio
    4. DCOP of refrigerator
    💡 Explanation:

    Adequate sigma prevents turbine cavitation at runner outlet.

  59. Q59medium

    Hydraulic efficiency of turbine is

    1. Awater power output divided by energy supplied in flow
    2. Belectrical output only without losses
    3. Cvolumetric efficiency of pump
    4. Dboiler efficiency
    💡 Explanation:

    ηh accounts for hydraulic losses in turbine passages.

  60. Q60medium

    Inverted U-tube manometer is used for

    1. Ahigh vacuum in steam condenser only always
    2. Bliquid flow in open channel only
    3. Cmeasuring torque
    4. Dmeasuring small pressure differences in gases
    💡 Explanation:

    Prevents manometer liquid from entering gas lines; suited for low Δp.

  61. Q61Past Paper · PPSC/FPSC/NTSeasy

    Barometer measures

    1. Agauge pressure in pipe always
    2. Bdynamic pressure only
    3. Clocal atmospheric pressure
    4. Dmass flow rate
    💡 Explanation:

    Mercury barometer column height corresponds to atmospheric pressure.

  62. Q62easy

    Gauge pressure equals

    1. Aabsolute plus atmospheric
    2. Bvacuum pressure always
    3. Ctwice absolute pressure
    4. Dabsolute pressure minus atmospheric pressure
    💡 Explanation:

    pgauge = pabs − patm; vacuum is below atmospheric.

  63. Q63easy

    Steady flow means

    1. Auniform flow at all cross sections always
    2. Bzero velocity everywhere
    3. CRe is constant in time only at inlet
    4. Dproperties at a point do not change with time
    💡 Explanation:

    Steady: partial derivatives with respect to time are zero at a fixed point.

  64. Q64Past Paper · PPSC/FPSC/NTSmedium

    Uniform flow in open channel implies

    1. Aonly steady in time
    2. Balways supercritical
    3. Calways laminar
    4. Ddepth and velocity constant along channel length
    💡 Explanation:

    Uniform: cross-section properties unchanged with distance at steady state.

  65. Q65easy

    Streamline is a line

    1. Atangent to velocity vector everywhere
    2. Bperpendicular to flow always
    3. Calong which pressure is zero
    4. Dof constant temperature only
    💡 Explanation:

    In steady flow streamlines coincide with particle paths.

  66. Q66medium

    Path line of fluid particle is

    1. Aalways straight line
    2. Bactual trajectory traced by that particle
    3. Csame as streak line always in unsteady flow
    4. Dalways parallel to wall
    💡 Explanation:

    Path line shows history of single particle motion.

  67. Q67Past Paper · PPSC/FPSC/NTSmedium

    Streak line is

    1. Ainstantaneous velocity direction only
    2. Bconstant pressure line
    3. Clocus of particles passing through a common point
    4. Dpipe centerline always
    💡 Explanation:

    Streak line is what dye visualization shows in flow.

  68. Q68hard

    Euler equation along streamline for inviscid flow relates

    1. Ashear stress to viscosity only
    2. Bheat transfer to conductivity
    3. Cpressure gradient to velocity and body force
    4. Dmass to moles
    💡 Explanation:

    dp/ρ + V dV + g dz = 0 for steady inviscid flow.

  69. Q69hard

    Navier-Stokes equations include

    1. Aonly hydrostatic terms
    2. Bviscous stress terms in momentum balance
    3. Ccombustion chemistry
    4. Delectromagnetic forces only
    💡 Explanation:

    NS equations add viscous diffusion to Euler momentum equation.

  70. Q70Past Paper · PPSC/FPSC/NTSmedium

    Transition from laminar to turbulent pipe flow depends on

    1. Apipe material color only
    2. Bonly pipe length
    3. CReynolds number and disturbances
    4. Dabsolute pressure only
    💡 Explanation:

    Re > 4000 typically turbulent; roughness and disturbances affect transition.

  71. Q71medium

    Hydraulic jump energy loss appears as

    1. Aincreased mechanical energy in flow
    2. Bstored elastic energy
    3. Cpump head gain
    4. Dturbulence and heat dissipation
    💡 Explanation:

    Jump converts kinetic energy of supercritical flow to internal energy.

  72. Q72Past Paper · PPSC/FPSC/NTSmedium

    Torricelli theorem gives exit velocity from tank as

    1. A√(gh/2)
    2. B2gh without root
    3. Czero if orifice is sharp
    4. D√(2gh)
    💡 Explanation:

    Ideal Torricelli: V = √(2gh) from energy balance with free surface.

  73. Q73hard

    Coefficient of velocity Cv for orifice is ratio of

    1. Aactual jet velocity to ideal velocity
    2. Bactual discharge to ideal area velocity product
    3. Cpressure to density
    4. Dhead loss to diameter
    💡 Explanation:

    Cv accounts for vena contracta and velocity reduction.

  74. Q74hard

    Coefficient of contraction Cc is ratio of

    1. Apipe area to orifice
    2. Bvena contracta area to orifice area
    3. Cvelocity to discharge
    4. DRe to friction factor
    💡 Explanation:

    Cc < 1 due to jet contraction downstream of sharp orifice.

  75. Q75Past Paper · PPSC/FPSC/NTShard

    Cd for orifice equals approximately

    1. ACv times Cc
    2. BCv divided by Cc
    3. CCv plus Cc
    4. D1 always
    💡 Explanation:

    Discharge coefficient combines velocity and contraction effects.

  76. Q76medium

    Blower differs from compressor in that blower provides

    1. Avery high pressure ratio like multistage compressor
    2. Brelatively small pressure rise at high volume flow
    3. Conly vacuum suction
    4. Dliquid pumping
    💡 Explanation:

    Fans and blowers handle large volumes at low Δp; compressors higher ratio.

  77. Q77medium

    Axial flow pump is preferred when

    1. Alarge discharge at low head is required
    2. Bvery high head low flow
    3. Chandling highly viscous paste
    4. Dmetering precise microliters
    💡 Explanation:

    Propeller-type impeller for irrigation and cooling water circulation.

  78. Q78Past Paper · PPSC/FPSC/NTSeasy

    Foot valve on pump suction line prevents

    1. Acavitation entirely always
    2. Breverse rotation of motor
    3. Cdrainage of pipe and loss of prime when pump stops
    4. Dincrease in NPSHr
    💡 Explanation:

    One-way valve keeps suction line filled with liquid.

  79. Q79easy

    Priming of centrifugal pump is necessary because

    1. Acentrifugal pump cannot handle air and must be filled with liquid
    2. Bit increases impeller diameter
    3. Cit reduces NPSHa
    4. Dit converts reciprocating to rotary motion
    💡 Explanation:

    Without liquid, impeller cannot create sufficient vacuum to lift air.

  80. Q80easy

    Differential manometer connected across venturi throat and inlet measures

    1. Aabsolute atmospheric pressure only
    2. Bpressure difference used to calculate flow rate
    3. Cfluid viscosity directly without formula
    4. Dturbine shaft power
    💡 Explanation:

    Manometer deflection with ρ and g gives Δp for venturi/orifice flow equation.