Strength of Materials and Machine Design MCQs 2026

90 questions with detailed answers · 32 from past papers · 9 quiz batches available

📚 Mechanical Engineering📄 32 Past-Paper Qs✓ Free · No Login Needed
🎯 Mock Test

Read each question, think about the answer, then click Show Answer to reveal the correct option and explanation. Load 10 at a time so it stays manageable — perfect for one-topic study sessions on the bus or during a break.

Page 1 of 1Questions 1–10 of 90
  1. Q1medium

    Strain hardening increases

    1. Aductility always without limit always
    2. Byield strength after plastic deformation
    3. Celastic modulus greatly always
    4. Ddensity significantly
    💡 Explanation:

    Cold working raises strength, reduces ductility.

  2. Q2Past Paper · PPSC/FPSC/NTSmedium

    Saint-Venant's principle states localized end effects decay within

    1. Aentire beam length always
    2. Bzero distance
    3. Cinfinite distance always
    4. Dcharacteristic dimension of cross-section
    💡 Explanation:

    Far-field stresses independent of end detail.

  3. Q3hard

    Beam column combines

    1. Apure torsion only
    2. Bonly heat conduction
    3. Caxial compression and bending causing instability interaction
    4. Donly mass diffusion only
    💡 Explanation:

    P-δ effect reduces capacity.

  4. Q4hard

    Hertz contact stress occurs between

    1. Aonly fluids at rest
    2. Bcurved bodies in elastic contact
    3. Conly ideal gases in piston only without contact mechanics
    4. Donly radiation surfaces
    💡 Explanation:

    Point/line contact local pressure.

  5. Q5Past Paper · PPSC/FPSC/NTShard

    Design against buckling uses critical slenderness to separate

    1. Afatigue vs creep only
    2. Bconduction vs convection only
    3. CEuler buckling vs yield failure modes
    4. DOtto vs Diesel only
    💡 Explanation:

    Johnson parabola bridges elastic buckling and yield.

  6. Q6medium

    Shock loading factor accounts for

    1. Adynamic magnification over static load
    2. Bonly thermal expansion
    3. Conly laminar boundary layer
    4. Donly isentropic flow
    💡 Explanation:

    Impact factors increase design load.

  7. Q7hard

    Stress relaxation in bolt at constant extension over time causes

    1. Aincrease in preload always
    2. Bdecrease in bolt tension
    3. Cno change ever
    4. Dincrease in joint separation always immediately
    💡 Explanation:

    Creep/relaxation reduces preload.

  8. Q8Past Paper · PPSC/FPSC/NTSmedium

    Impact toughness is tested by

    1. ACharpy or Izod notched bar impact test
    2. Btensile test only always
    3. Chardness only always
    4. Dcreep test at low stress only
    💡 Explanation:

    Energy absorbed indicates toughness.

  9. Q9Past Paper · PPSC/FPSC/NTSmedium

    Splined connection allows

    1. Aonly welded joint behavior
    2. Bno alignment capability
    3. Conly tensile load never torque
    4. Dtorque transmission with axial sliding possible
    💡 Explanation:

    Splines used in gearboxes and clutches.

  10. Q10easy

    Set screw transmits torque primarily by

    1. Akeyway shear always required
    2. Bfriction and indentation at contact
    3. Csplines only always
    4. Dwelding only
    💡 Explanation:

    Set screws rely on friction/embedding.

  11. Q11medium

    Proof load testing of bolt verifies

    1. Aultimate fracture always required
    2. Bonly torque without tension
    3. Chardness only
    4. Dability to sustain specified load without permanent elongation beyond limit
    💡 Explanation:

    Proof stress checks elastic behavior margin.

  12. Q12Past Paper · PPSC/FPSC/NTShard

    Notch sensitivity in fatigue depends on

    1. Aonly applied voltage
    2. Bonly fluid density
    3. Conly color of surface
    4. Dmaterial and notch geometry
    💡 Explanation:

    q factor relates Kt to fatigue stress concentration.

  13. Q13medium

    Creep in materials at high temperature is

    1. Ainstant elastic recovery only
    2. Btime-dependent permanent deformation under constant stress
    3. Cfatigue at one cycle
    4. Donly buckling
    💡 Explanation:

    Creep important in turbines and boilers.

  14. Q14medium

    Residual stress in welded joint arises from

    1. Aonly external tensile load
    2. Bonly centrifugal force
    3. Cnon-uniform heating and cooling
    4. Donly laminar flow
    💡 Explanation:

    Thermal cycles leave locked-in stresses.

  15. Q15Past Paper · PPSC/FPSC/NTSmedium

    Torsional rigidity of shaft is

    1. AE I
    2. BG J
    3. CP/A
    4. Dρ g h
    💡 Explanation:

    GJ measures resistance to twist per unit length.

  16. Q16medium

    Relation M = E I d²y/dx² assumes

    1. Alarge deflection plasticity always included
    2. Bshear deformation dominant always
    3. Cthermal loading absent always required incorrectly
    4. Dsmall deflections and linear elastic material
    💡 Explanation:

    Beam theory with Bernoulli-Euler assumptions.

  17. Q17medium

    Deflection curve slope equals

    1. Asecond derivative only always
    2. Bfirst derivative of deflection with respect to x
    3. Cintegral of M only without relation
    4. Dshear force directly always
    💡 Explanation:

    θ = dy/dx from elastic curve.

  18. Q18Past Paper · PPSC/FPSC/NTShard

    Shear center of open thin-walled channel section lies

    1. Aat geometric centroid always
    2. Bat farthest fiber always
    3. Cat infinity always
    4. Doutside the cross-section on web side
    💡 Explanation:

    Loads through shear center avoid twisting.

  19. Q19medium

    Eccentric loading on column introduces

    1. Aonly torsion
    2. Bonly shear without axial
    3. Ccombined axial stress and bending stress
    4. Dzero stress
    💡 Explanation:

    M = P e adds bending to axial.

  20. Q20Past Paper · PPSC/FPSC/NTShard

    von Mises yield criterion is based on

    1. Amaximum principal stress only for all materials always
    2. Bdistortion energy
    3. Cvolume change only
    4. Dthermal stress only
    💡 Explanation:

    Equivalent stress from distortion energy theory.

  21. Q21medium

    Maximum normal stress theory (Rankine) is suitable for

    1. Abrittle materials in tension
    2. Bductile combined loading always better with von Mises
    3. Cany rubber behavior
    4. Dfluid flow only
    💡 Explanation:

    Failure when max principal stress reaches ultimate.

  22. Q22hard

    Castigliano's theorem relates deflection to

    1. Athermal expansion only
    2. Bpartial derivative of strain energy with respect to load
    3. Centropy only
    4. D Reynolds number only
    💡 Explanation:

    δ = ∂U/∂P for linear elastic systems.

  23. Q23Past Paper · PPSC/FPSC/NTSmedium

    Strain energy per unit volume in elastic uniaxial stress is

    1. Aσ E
    2. BE/σ
    3. Cσ²/(2E)
    4. Dσ E²
    💡 Explanation:

    U = ½ σ ε = σ²/(2E).

  24. Q24hard

    Maximum shear stress in thin cylinder under internal pressure occurs at

    1. Ainner surface for thick wall; approximately uniform for thin
    2. Bouter surface only always
    3. Cmid-wall only for thin always incorrectly always
    4. Dzero everywhere
    💡 Explanation:

    Inner radius sees highest hoop stress in thick cylinders.

  25. Q25hard

    Thick cylinder analysis uses

    1. Aonly thin wall formula always
    2. Bonly Euler buckling formula
    3. Conly Fourier law
    4. DLamé equations with radial and hoop stress variation
    💡 Explanation:

    Lamé solutions account for radial stress gradient.

  26. Q26Past Paper · PPSC/FPSC/NTSmedium

    Longitudinal stress in thin cylinder is

    1. Ap r / t
    2. B2 p r / t
    3. Cp r / (2t)
    4. Dzero always
    💡 Explanation:

    σ_l = pr/(2t) half of hoop for thin cylinder.

  27. Q27medium

    Thin cylinder with internal pressure p and radius r has hoop stress

    1. Ap r / t
    2. Bp t / r
    3. Cp r t
    4. Dp / (r t) only without relation
    💡 Explanation:

    σ_h = pr/t for thin wall t << r.

  28. Q28hard

    Wahl factor accounts for

    1. Aonly buckling in columns
    2. Bonly radiation heat transfer
    3. Ccurvature and direct shear in spring wire stress
    4. Donly entropy generation
    💡 Explanation:

    Corrects τ = 16T/(πd³) for springs.

  29. Q29Past Paper · PPSC/FPSC/NTSmedium

    Spring index C is ratio of

    1. Awire diameter to coil diameter
    2. Bfree length to solid length always
    3. Cload to deflection only
    4. Dmean coil diameter to wire diameter
    💡 Explanation:

    C = D/d affects stress and manufacturability.

  30. Q30hard

    Helical compression spring rate k equals

    1. AG d⁴ / (8 D³ N) for active coils N
    2. BE I / L
    3. CP/A only
    4. DT/J only
    💡 Explanation:

    Spring stiffness from wire and coil geometry.

  31. Q31medium

    Hollow shaft compared to solid of same weight has

    1. Alower torsional stiffness always
    2. Bhigher polar moment of inertia
    3. Csame J always
    4. Dzero shear stress
    💡 Explanation:

    Material placed farther from axis increases J.

  32. Q32Past Paper · PPSC/FPSC/NTShard

    Shaft design for combined bending and torsion often uses

    1. Aonly axial stress formula
    2. Bequivalent bending or torsion theories
    3. Conly thermal expansion
    4. Donly Bernoulli equation
    💡 Explanation:

    Equivalent moment/te torque per ASME or other codes.

  33. Q33hard

    Woodruff key is

    1. Asquare parallel key only
    2. Bsplined shaft only
    3. Csemicircular disk key for tapered hubs
    4. Dset screw only
    💡 Explanation:

    Used with tapered hubs on shafts.

  34. Q34medium

    Square key transmits torque between shaft and hub by

    1. Atension in key only
    2. Btorsion in key as primary mode always
    3. Cfriction only without bearing
    4. Dshear and bearing on key sides
    💡 Explanation:

    Key fails in shear/bearing if overloaded.

  35. Q35easy

    Modulus of elasticity E has units of

    1. Adimensionless only
    2. Bm/s
    3. CPa or N/m²
    4. DN·m
    💡 Explanation:

    E relates stress and strain; same units as stress.

  36. Q36easy

    Hooke's law in elastic range states

    1. Astress equals strain always
    2. Bstrain is independent of stress
    3. Cstress equals modulus only without strain
    4. Dstress is proportional to strain
    💡 Explanation:

    σ = E ε within proportional limit.

  37. Q37Past Paper · PPSC/FPSC/NTSeasy

    Shear stress τ is given by

    1. Anormal force divided by area
    2. Bforce times moment arm
    3. Ctangential force divided by area
    4. Dstrain divided by time
    💡 Explanation:

    τ = V/A for direct shear.

  38. Q38Past Paper · PPSC/FPSC/NTSeasy

    Normal stress on a plane is defined as

    1. Aforce parallel to area divided by volume
    2. Bmoment divided by area
    3. Cstrain times modulus only
    4. Dforce perpendicular to area divided by area
    💡 Explanation:

    σ = P/A for axial loading.

  39. Q39hard

    Goodman line in fatigue relates

    1. Athermal stress and strain only
    2. Bmean and alternating stress for failure
    3. Cbuckling load and length only
    4. Dtorque and power only
    💡 Explanation:

    Modified Goodman criterion for fatigue.

  40. Q40hard

    Bolt subjected to axial external load shares load with

    1. Aonly nut always
    2. Bconnected members due to joint stiffness
    3. Conly washer friction without members
    4. Dair gap only
    💡 Explanation:

    Load sharing depends on bolt and member stiffness.

  41. Q41Past Paper · PPSC/FPSC/NTSmedium

    Poisson's ratio ν is defined as

    1. Aaxial strain divided by lateral strain
    2. Bshear strain divided by normal strain always
    3. Cstress divided by strain squared
    4. Dlateral strain divided by axial strain with opposite sign
    💡 Explanation:

    ν = −ε_lateral/ε_axial for uniaxial loading.

  42. Q42easy

    For a bar in simple tension, maximum normal stress occurs on

    1. Aplane at 45° to load always for max
    2. Bplane parallel to load
    3. Cany plane equally
    4. Dplane perpendicular to load
    💡 Explanation:

    Axial stress is maximum on cross section normal to force.

  43. Q43medium

    Shear strain γ is approximately

    1. Achange in right angle between originally perpendicular lines
    2. Bratio of normal stresses
    3. Cchange in volume only
    4. Dstress divided by E only
    💡 Explanation:

    γ measures angular distortion.

  44. Q44Past Paper · PPSC/FPSC/NTSmedium

    Modulus of rigidity G relates

    1. Anormal stress and lateral strain only
    2. Bbulk modulus and pressure only
    3. Cshear stress and shear strain
    4. Dthermal expansion and temperature
    💡 Explanation:

    τ = G γ in elastic shear.

  45. Q45medium

    Bulk modulus K measures resistance to

    1. Auniform volumetric compression
    2. Bbending only
    3. Ctorsion only
    4. Dfatigue cracking only
    💡 Explanation:

    K = −p / (ΔV/V).

  46. Q46easy

    Factor of safety is generally defined as

    1. Aworking stress divided by failure strength
    2. Balways equal to 1
    3. Cload divided by deflection
    4. Dfailure strength divided by allowable or working stress
    💡 Explanation:

    FOS > 1 provides design margin.

  47. Q47Past Paper · PPSC/FPSC/NTSeasy

    In bending, neutral axis is the locus of points where

    1. Ashear stress is maximum always
    2. Bnormal stress is maximum always
    3. Cdeflection is maximum
    4. Dlongitudinal strain is zero
    💡 Explanation:

    NA separates tension and compression zones.

  48. Q48medium

    Flexure formula σ = My/I applies to

    1. Aelastic homogeneous beam in pure bending
    2. Bplastic collapse always
    3. Cany shape without NA
    4. Dtorsion of circular shaft
    💡 Explanation:

    Bending stress varies linearly with y from NA.

  49. Q49medium

    Section modulus Z equals

    1. AI divided by distance to extreme fiber c
    2. BI times c
    3. CI plus c
    4. Dc divided by I
    💡 Explanation:

    Z = I/c used in σ = M/Z.

  50. Q50Past Paper · PPSC/FPSC/NTSmedium

    Maximum shear stress in rectangular beam occurs at

    1. Atop fiber only
    2. Bbottom fiber only
    3. Cquarter depth from NA always for all sections
    4. Dneutral axis
    💡 Explanation:

    Parabolic shear distribution peaks at NA for rectangle.

  51. Q51hard

    Deflection of simply supported beam with central point load is proportional to

    1. AL³/(E I)
    2. BL only
    3. C1/I only without E
    4. DE I only without L
    💡 Explanation:

    δ ∝ PL³/(E I) for given loading.

  52. Q52Past Paper · PPSC/FPSC/NTSmedium

    Torsion formula τ = T r / J applies to

    1. Acircular shafts in elastic range
    2. Bany non-circular section without correction
    3. Cbeams in pure bending
    4. Dthick cylinders under internal pressure only
    💡 Explanation:

    Circular cross-section with J polar moment.

  53. Q53medium

    Angle of twist for shaft is φ =

    1. AT G / (L J)
    2. BT L / (G J)
    3. CG J L / T
    4. DJ / (T L G)
    💡 Explanation:

    Elastic torsion relation.

  54. Q54easy

    Solid circular shaft polar moment J equals

    1. Aπ d²/4
    2. Bπ d³/16
    3. Cπ d⁴/32
    4. Dbh³/12
    💡 Explanation:

    Standard torsion constant.

  55. Q55Past Paper · PPSC/FPSC/NTSmedium

    Hollow shaft is preferred when

    1. Aweight reduction with similar torsional strength is needed
    2. Bonly bending dominates always
    3. Cno shear stress exists
    4. Dmaterial is brittle only
    💡 Explanation:

    Material farther from axis carries more shear.

  56. Q56medium

    Mohr's circle for plane stress plots

    1. Aonly principal strains without stress
    2. Bnormal and shear stress on various planes
    3. Conly thermal gradients
    4. Donly fatigue cycles
    💡 Explanation:

    Graphical tool for stress transformation.

  57. Q57medium

    Principal stresses are stresses on planes where

    1. Anormal stress is zero
    2. Bboth stresses are equal always
    3. Cstrain is maximum always
    4. Dshear stress is zero
    💡 Explanation:

    Principal planes have τ = 0.

  58. Q58Past Paper · PPSC/FPSC/NTShard

    Maximum shear stress in plane stress equals

    1. Aradius of Mohr's circle
    2. Bsum of principal stresses
    3. Cdifference of principal strains
    4. Dzero always
    💡 Explanation:

    τ_max = (σ1 − σ2)/2.

  59. Q59hard

    Euler column buckling load for pinned-pinned column is

    1. Aπ² E I / L²
    2. BE I / L
    3. Cπ E I / L
    4. D4 π² E I / L² always
    💡 Explanation:

    Critical load P_cr = π²EI/L² for end condition factor 1.

  60. Q60medium

    Effective length of column fixed at one end and free at other is

    1. AL/2
    2. BL
    3. C2L
    4. D0.7 L
    💡 Explanation:

    Equivalent pinned length 2L for standard end condition.

  61. Q61Past Paper · PPSC/FPSC/NTSmedium

    Slenderness ratio for column is

    1. Adiameter divided by length
    2. Bstress divided by strain
    3. Ceffective length divided by least radius of gyration
    4. Dload divided by area only
    💡 Explanation:

    λ = Le/k governs buckling mode.

  62. Q62easy

    Fatigue failure occurs at stress

    1. Abelow static yield strength under cyclic loading
    2. Bonly above ultimate strength always
    3. Conly in single static overload
    4. Donly at zero mean stress always
    💡 Explanation:

    Progressive damage under repeated loads.

  63. Q63medium

    Endurance limit on S-N curve for ferrous materials in reversed bending often occurs near

    1. A10⁶ cycles
    2. B10³ cycles
    3. C10⁹ cycles always for all materials
    4. Done cycle only
    💡 Explanation:

    Horizontal asymptote of S-N curve for steel.

  64. Q64Past Paper · PPSC/FPSC/NTSmedium

    Stress concentration factor Kt is ratio of

    1. Anominal to maximum stress
    2. Bfatigue limit to yield
    3. Cmaximum local stress to nominal stress
    4. Dshear to normal stress always
    💡 Explanation:

    Kt > 1 at geometric discontinuities.

  65. Q65easy

    Hardness test indentation measures

    1. Aonly thermal conductivity
    2. Bonly electrical resistivity
    3. Cresistance to permanent deformation
    4. Donly fatigue life directly always accurately
    💡 Explanation:

    Brinell/Rockwell/Vickers relate to strength empirically.

  66. Q66medium

    Necking in tensile test begins at

    1. Aultimate tensile strength point
    2. Byield point always
    3. Cproportional limit
    4. Delastic limit only for brittle
    💡 Explanation:

    Instability after UTS.

  67. Q67Past Paper · PPSC/FPSC/NTSmedium

    Yield point for mild steel shows

    1. Aperfectly linear behavior to fracture
    2. Bno plastic region
    3. Cupper and lower yield phenomenon
    4. Dnegative Poisson ratio always
    💡 Explanation:

    Lüders bands may appear at yield.

  68. Q68easy

    Proportional limit is stress at which

    1. Afracture occurs
    2. Bstress-strain deviates from linearity
    3. Cnecking completes always
    4. Dhardness equals toughness
    💡 Explanation:

    End of Hookean region.

  69. Q69easy

    Gauge length in tensile test standard specimen affects

    1. Ayield strength fundamentally for same material incorrectly always
    2. Bmodulus E value fundamentally incorrectly always
    3. Cmeasured elongation and reported strain
    4. Ddensity of specimen
    💡 Explanation:

    Extensometer/gauge length standardized (e.g. 50 mm).

  70. Q70Past Paper · PPSC/FPSC/NTShard

    Brittle coating method in stress analysis uses

    1. Acracking pattern to indicate strain direction/magnitude
    2. Bthermocouples only
    3. CPitot tube only
    4. Dorifice meter only
    💡 Explanation:

    Photoelastic/brittle lacquer techniques.

  71. Q71medium

    Efficiency of riveted joint is ratio of

    1. Anumber of rivets to length only
    2. Bstrength of riveted joint to solid plate strength
    3. Cpitch to diameter only without strength
    4. Dweight to volume only
    💡 Explanation:

    Joint efficiency < 1 due to holes.

  72. Q72Past Paper · PPSC/FPSC/NTSmedium

    Riveted joint failure modes include

    1. Aonly buckling of rivet head always alone
    2. Bonly corrosion without mechanics
    3. Conly torsion of plate
    4. Dshearing of rivet, bearing, tearing of plate
    💡 Explanation:

    Multiple failure paths analyzed.

  73. Q73medium

    Cotter joint is used for

    1. Asealing steam turbine blades only
    2. Bconnecting two rods under axial load with wedge pin
    3. Cmeasuring viscosity only
    4. Drankine pump only
    💡 Explanation:

    Cotter wedge provides axial holding.

  74. Q74medium

    Knuckle joint transmits

    1. Apure torsion only always
    2. Btensile load in rods with pin connection
    3. Chydraulic pressure in pipes only
    4. Dheat by radiation only
    💡 Explanation:

    Pin joint for tie rods.

  75. Q75Past Paper · PPSC/FPSC/NTShard

    Surge in spring occurs when

    1. Aspring is static only
    2. Bnatural frequency of spring-mass matches forcing frequency
    3. Conly compression without coils
    4. Dtemperature is constant only
    💡 Explanation:

    Surge waves cause coil collision.

  76. Q76easy

    Leaf spring is a form of

    1. Apure torsion spring only
    2. Bthin cylinder only
    3. Cbeam bending with multiple leaves
    4. Drankine cycle component
    💡 Explanation:

    Truck suspensions use laminated leaf springs.

  77. Q77medium

    Gasketed flange joint leakage prevention relies on

    1. Azero bolt torque
    2. Bonly paint sealant without load
    3. Csufficient gasket compression from bolt preload
    4. Dshear keys only
    💡 Explanation:

    Preload maintains gasket seal stress.

  78. Q78Past Paper · PPSC/FPSC/NTShard

    Stress in bolt due to external tensile load increases less than external load when

    1. Aplates have zero stiffness
    2. Bbolt has zero stiffness
    3. Cno preload exists always giving full external load on bolt incorrectly stated as always
    4. Dconnected plates are stiff and carry share of load
    💡 Explanation:

    Stiff plates reduce ΔP_bolt.

  79. Q79hard

    Closed thin-walled tube in torsion resists torque by

    1. Aonly bending of walls without shear flow
    2. Baxial tension only
    3. Cinternal pressure only
    4. Dshear flow around perimeter (Bredt-Batho)
    💡 Explanation:

    Closed sections efficient in torsion.

  80. Q80hard

    Shear flow q in thin-walled section equals

    1. AM y / I only always alone for shear flow
    2. BT r / J for open section primary bending shear
    3. CP/A only
    4. DV Q / I
    💡 Explanation:

    q = VQ/I for built-up sections.

  81. Q81Past Paper · PPSC/FPSC/NTSeasy

    Section modulus for rectangular section bh²/6 uses

    1. Ab and h as width and depth with bending about horizontal NA
    2. Bpolar diameter only
    3. Cradius only
    4. Dthickness of cylinder wall only
    💡 Explanation:

    Z = bh²/6 for bending about horizontal axis.

  82. Q82medium

    Strain rosette measures

    1. Anormal strains at three orientations to find principal strains
    2. Btemperature only
    3. Chardness only
    4. Dflow rate only
    💡 Explanation:

    Used in experimental stress analysis.

  83. Q83hard

    Compound bar of two materials in parallel under load shares strain and

    1. Atotal load according to stiffness EA sum
    2. Bstress equally always regardless of E
    3. Cload only by larger area alone always
    4. Dno load in stiffer material
    💡 Explanation:

    ε same; P = σ1A1 + σ2A2.

  84. Q84Past Paper · PPSC/FPSC/NTSmedium

    Thermal stress in restrained bar heated uniformly is

    1. Azero always even if restrained
    2. BE α ΔT (compressive if heated and restrained)
    3. Cα ΔT only without E
    4. DE/α ΔT
    💡 Explanation:

    Restrained expansion induces σ = EαΔT.

  85. Q85medium

    Principal strain in isotropic material under uniaxial stress includes

    1. Aonly axial strain without lateral
    2. Bzero strain transverse always
    3. Clateral strain from Poisson effect
    4. Dshear strain equal to normal strain
    💡 Explanation:

    ε_y = −ν ε_x for uniaxial σ_x.

  86. Q86hard

    Macaulay's method is used for

    1. Atorsion of non-circular bars only always analytically simple
    2. Bbeam deflection with discontinuous loading
    3. Crankine cycle analysis
    4. Dradiation view factors only
    💡 Explanation:

    Singularity functions simplify integration.

  87. Q87Past Paper · PPSC/FPSC/NTShard

    Beam with fixed ends carries less maximum moment than simply supported for same central load because

    1. Aload disappears
    2. BE is higher always
    3. CI is zero
    4. Dnegative moments at supports reduce midspan moment
    💡 Explanation:

    Indeterminate structure redistributes moments.

  88. Q88hard

    Critical speed of shaft occurs when

    1. Atorque is maximum only
    2. Bstress is zero
    3. Crotational speed equals natural frequency of lateral vibration
    4. Dbearing friction is zero only
    💡 Explanation:

    Resonance causes large deflections.

  89. Q89easy

    Coupling used to connect misaligned shafts elastically may be

    1. Arigid flange only for large misalignment always
    2. Bflexible coupling with elastomer element
    3. Ckey only without hub
    4. Dset screw on glass shaft
    💡 Explanation:

    Flexible couplings accommodate misalignment.

  90. Q90Past Paper · PPSC/FPSC/NTSmedium

    Initial tightening torque on bolt creates

    1. Apreload in shank
    2. Bonly shear in plate without axial force
    3. Czero stress always
    4. Donly bending always
    💡 Explanation:

    Torque induces axial tension via thread friction.