Random Variables and Mathematical Expectation MCQs 2026
49 questions with detailed answers · 29 from past papers · 5 quiz batches available
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- Q1Past Paper · PPSC/FPSC/CSSeasy
A random variable is
💡 Explanation:X(ω) maps outcomes to numbers for algebraic treatment.
- Q2Past Paper · PPSC/FPSC/CSSeasy
A discrete random variable takes
💡 Explanation:Discrete RVs have jump probabilities at specific points.
- Q3Past Paper · PPSC/FPSC/CSSeasy
A continuous random variable takes
💡 Explanation:Continuous RVs are modeled with density over intervals.
- Q4Past Paper · PPSC/FPSC/CSSeasy
The probability mass function (PMF) p(x) gives
💡 Explanation:PMF assigns probabilities to individual discrete values.
- Q5Past Paper · PPSC/FPSC/CSSeasy
A valid PMF must satisfy
💡 Explanation:PMF is non-negative and totals to 1.
- Q6Past Paper · PPSC/FPSC/CSSeasy
The probability density function (PDF) f(x) for continuous X satisfies
💡 Explanation:PDF integrates to 1; point probability is zero for continuous X.
- Q7Past Paper · PPSC/FPSC/CSSmedium
For continuous X, P(a ≤ X ≤ b) equals
💡 Explanation:Probability is area under the PDF over the interval.
- Q8Past Paper · PPSC/FPSC/CSSeasy
The cumulative distribution function F(x) is defined as
💡 Explanation:CDF gives left-tail probability up to x.
- Q9Past Paper · PPSC/FPSC/CSSeasy
For any CDF, lim_{x→−∞} F(x) equals
💡 Explanation:No mass below −∞.
- Q10Past Paper · PPSC/FPSC/CSSeasy
For any CDF, lim_{x→+∞} F(x) equals
💡 Explanation:All probability accumulated by +∞.
- Q11medium
A CDF is always
💡 Explanation:F(x2) ≥ F(x1) if x2 ≥ x1.
- Q12medium
For discrete X, F(x) is
💡 Explanation:CDF jumps by p(x) at each possible value.
- Q13Past Paper · PPSC/FPSC/CSSeasy
The expected value E(X) of discrete X equals
💡 Explanation:Expectation is the probability-weighted average of X.
- Q14Past Paper · PPSC/FPSC/CSSmedium
For X with PMF: x=0,p=0.2; x=1,p=0.5; x=2,p=0.3, E(X) equals
💡 Explanation:E(X) = 0×0.2 + 1×0.5 + 2×0.3 = 0.5 + 0.6 = 1.1.
- Q15Past Paper · PPSC/FPSC/CSSmedium
For the same distribution, E(X²) equals
💡 Explanation:E(X²) = 0²×0.2 + 1²×0.5 + 2²×0.3 = 0 + 0.5 + 1.2 = 1.7.
- Q16Past Paper · PPSC/FPSC/CSSmedium
For the same distribution, Var(X) equals
💡 Explanation:Var(X) = E(X²) − [E(X)]² = 1.7 − 1.21 = 0.49.
- Q17Past Paper · PPSC/FPSC/CSSeasy
Variance Var(X) is defined as
💡 Explanation:Variance measures squared deviation from the mean.
- Q18Past Paper · PPSC/FPSC/CSSeasy
The standard deviation σ equals
💡 Explanation:σ = √Var(X) restores original units.
- Q19Past Paper · PPSC/FPSC/CSSeasy
Linearity of expectation gives E(aX + b) as
💡 Explanation:Expectation is linear regardless of independence.
- Q20Past Paper · PPSC/FPSC/CSSmedium
If X and Y are independent, E(XY) equals
💡 Explanation:Independence factorizes expectation of product.
- Q21Past Paper · PPSC/FPSC/CSSmedium
Var(aX + b) equals
💡 Explanation:Adding constant b does not affect spread; scaling squares in variance.
- Q22Past Paper · PPSC/FPSC/CSSmedium
If X and Y are independent, Var(X + Y) equals
💡 Explanation:Variances add for independent sums.
- Q23Past Paper · PPSC/FPSC/CSSeasy
The PMF of a Bernoulli(p) trial is
💡 Explanation:Bernoulli models one success/failure with parameter p.
- Q24Past Paper · PPSC/FPSC/CSSeasy
For Bernoulli(p), E(X) equals
💡 Explanation:E(X) = 0×(1−p) + 1×p = p.
- Q25Past Paper · PPSC/FPSC/CSSmedium
For Bernoulli(p), Var(X) equals
💡 Explanation:Var = p − p² = p(1−p).
- Q26easy
The mode of a distribution is
💡 Explanation:Mode is the most likely value.
- Q27medium
The median m satisfies
💡 Explanation:Median splits the distribution in half.
- Q28medium
The relationship between PDF and CDF is
💡 Explanation:Differentiating CDF yields PDF for continuous X.
- Q29hard
For discrete X, recovering PMF from CDF: p(x) equals
💡 Explanation:Jump size in CDF equals point mass.
- Q30hard
Chebyshev's inequality bounds
💡 Explanation:Chebyshev holds for any distribution with finite variance.
- Q31Past Paper · PPSC/FPSC/CSSeasy
A fair die score X. E(X) equals
💡 Explanation:E(X) = (1+2+3+4+5+6)/6 = 21/6 = 3.5.
- Q32hard
For fair die X, Var(X) equals
💡 Explanation:E(X²)=(1+4+9+16+25+36)/6=91/6; Var=91/6−12.25=35/12≈2.917.
- Q33Past Paper · PPSC/FPSC/CSSmedium
If Y = 2X + 3 and E(X)=4, Var(X)=5, then E(Y) equals
💡 Explanation:E(Y) = 2×4 + 3 = 11.
- Q34Past Paper · PPSC/FPSC/CSSmedium
With the same Y = 2X + 3, Var(Y) equals
💡 Explanation:Var(Y) = 2²×5 = 20.
- Q35medium
Joint PMF p(x,y) gives
💡 Explanation:Joint PMF specifies simultaneous probabilities.
- Q36medium
Marginal PMF p_X(x) is found by
💡 Explanation:Marginalization sums (or integrates) out other variables.
- Q37Past Paper · PPSC/FPSC/CSSmedium
X and Y are independent iff
💡 Explanation:Independence factorizes the joint distribution.
- Q38Past Paper · PPSC/FPSC/CSSmedium
Cov(X,Y) = E(XY) − E(X)E(Y). If independent, Cov(X,Y) equals
💡 Explanation:Independence implies zero covariance (converse not always true).
- Q39medium
Correlation ρ(X,Y) equals
💡 Explanation:Correlation is standardized covariance in [−1,1].
- Q40hard
A function g(X) is a random variable. E[g(X)] for discrete X equals
💡 Explanation:LOTUS: expectation of function uses same weights p(x).
- Q41hard
Jensen's inequality for convex g states E[g(X)] is
💡 Explanation:Convex functions: average of g ≥ g of average.
- Q42hard
The moment generating function M(t) = E(e^{tX}) helps find moments because
💡 Explanation:Differentiate MGF and evaluate at 0 for moments.
- Q43medium
Percentile p_k satisfies
💡 Explanation:k-th percentile is value with k% below it.
- Q44easy
Interquartile range (IQR) equals
💡 Explanation:IQR spans middle 50% of data/distribution.
- Q45Past Paper · PPSC/FPSC/CSSeasy
For X uniform on {1,2,3,4}, E(X) equals
💡 Explanation:E(X) = (1+2+3+4)/4 = 10/4 = 2.5.
- Q46hard
A RV with E(X)=μ and Var(X)=0 must satisfy
💡 Explanation:Zero variance means no spread: degenerate at μ.
- Q47medium
The law of large numbers states that
💡 Explanation:LLN: X̄ₙ → μ in probability under iid finite μ.
- Q48easy
A probability histogram for discrete data uses
💡 Explanation:Bar area/height represents probability mass at each value.
- Q49medium
The coefficient of variation CV equals
💡 Explanation:CV measures relative variability, useful for comparing scales.